physics

a car moving on a straight road with a speed of 20m/s. at t=0 the driver of the car applies the breaks after watching an obstacle 150m ahead. after application of breaks, the car retards with 2m/s^2. find the position of the car from the obstacle at t=15s.

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  1. d = 20(15) -(1/2)(2)(15^2)
    = 300 - 225 = 75 m
    150 - 75 = 75

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    posted by Damon
  2. Post it.

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    posted by Henry

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