A 0.15 kg baseball moving at +26 m/s is slowed to a stop by a catcher who exerts a constant force of -390 N. How long does it take this force to stop the ball? How far does the ball travel before stopping?

plz plz plz help!!

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1. Use the impulse-momentum wethod to answer this question. The impulse is the average force Fav, multipled bu the tme that it is applied (which is the time it takes to decelerate the ball).

|Fav| * T = 0.15 kg * 26 m/s

We only need the absolute value of the force, so never mind the minus sign in front of -390N.

T = .015*26/390 = ? seconds

The distance X travelled while stopping equals average velocity x Time
X = (1/2)V^2*M/Fav

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2. .01s

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