Sue and Jenny kick a soccer ball at exactly the same time.Sue's foot exerts a force of 62.3 N to the north. Jenny's foot exerts a force of 115.9 N to the east. What is the magnitude of the resultant force on the ball? Answer in N.

What is the direction of the resultant force (measured from the east)? Answer in degrees

This is what i did, but im not sure if my method is correct.:

squareroot of 62.3^2 + 115.9^2=131.6N

tan^-1 62.3/115.9=28.25 degrees

yes, that is the angle north of east

Your method is correct. The magnitude of the resultant force (F) can be calculated using the Pythagorean theorem:

F = √(62.3^2 + 115.9^2) = 131.6 N

The direction of the resultant force (θ) can be found using trigonometry (tan^-1):

θ = tan^-1(62.3/115.9) ≈ 28.25 degrees

So, the magnitude of the resultant force is 131.6 N, and the direction from the east is approximately 28.25 degrees.

Your method is correct!

To find the magnitude of the resultant force, you can use the Pythagorean theorem. The resultant force is the hypotenuse of a right triangle, with Sue's force (62.3 N) as one side and Jenny's force (115.9 N) as the other side.

Using the Pythagorean theorem, you correctly calculated the magnitude as the square root of the sum of the squares of the two forces:

Magnitude = √(62.3^2 + 115.9^2) = 131.6 N

To find the direction of the resultant force, you can use trigonometry. The angle can be determined by taking the inverse tangent (tan^-1) of the ratio of Sue's force to Jenny's force.

Direction = tan^-1(62.3/115.9) ≈ 28.25 degrees

So the magnitude of the resultant force is 131.6 N, and the direction (measured from the east) is approximately 28.25 degrees.