in triangle ABC,side AB IS 2cm. shorter than side AC, while side BC is 1cm. if the perimeter is 62 find the lenght of three sides? i need the answer tomorrow pls... help me
P=sum three sides
P=BC+Ab+Ac
62=AC+AC-2+1 solve for AC first, then AC-2 (which is AB) Are you certain about BC?
To find the lengths of the three sides of triangle ABC, we can use the information given.
Let's assume the length of side AC is x cm. Since side AB is 2 cm shorter than side AC, the length of side AB would be (x - 2) cm.
Given that side BC is 1 cm, we can now express the perimeter of the triangle:
Perimeter (P) = AB + BC + AC
Substituting the given values:
62 = (x - 2) + 1 + x
Simplifying the equation:
62 = 2x - 1
Rearranging the equation to isolate x:
2x = 63
x = 63/2
x = 31.5
Now, we know that side AC has a length of 31.5 cm. To find the length of side AB, we subtract 2 cm from the length of AC:
AB = AC - 2
= 31.5 - 2
= 29.5 cm
Therefore, the lengths of the sides are AB = 29.5 cm, BC = 1 cm, and AC = 31.5 cm.
Please note that this is a mathematical calculation, and the answer is accurate. However, since you need the answer tomorrow, it might be best to solve this problem yourself or seek assistance from a math teacher or tutor to ensure you understand the process.