# Chemistry

Given the following two step reaction:

4 P + 5 O2 -> P4O10

P4O10 + 6 H2O -> 4H3PO4

If you have 8.28 g of P, 15.65 g of O2, and 19.95 g of H2O, how many grams of H3PO4 can be produced?

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3. 👁 197
1. 4 P + 5 O2 -> P4O10
8.28g 15.65g
moles=g/mw x=15.65g/160.0
x=8.28/124.0 x= 0.0978
x=0.067

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2. 4 P
8.28g
m=g/mw
x=8.28/124.0
x=0.067

+ 502
15.65g
x=15.65g/160
x= 0.0978

= P4O10

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3. See the post above where I worked part of the problem.

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4. 40.9 grams produce

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