Chemistry

Given the following two step reaction:

4 P + 5 O2 -> P4O10

P4O10 + 6 H2O -> 4H3PO4

If you have 8.28 g of P, 15.65 g of O2, and 19.95 g of H2O, how many grams of H3PO4 can be produced?

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  1. 4 P + 5 O2 -> P4O10
    8.28g 15.65g
    moles=g/mw x=15.65g/160.0
    x=8.28/124.0 x= 0.0978
    x=0.067

    Which one would be limited? Please help if possible. Also, are my sigfigs correct?

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  2. 4 P
    8.28g
    m=g/mw
    x=8.28/124.0
    x=0.067

    + 502
    15.65g
    x=15.65g/160
    x= 0.0978

    = P4O10

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  3. See the post above where I worked part of the problem.

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  4. 40.9 grams produce

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