In an experiment, a seabird was taken from its nest, flown a distance 5190 km away, and released. It found its way back to its nest a time 13.8 days after release.
What was the bird's average velocity in m/s for the whole episode, from leaving the nest to returning?
Would I double the distance traveled to find the answer?
Because its displacement (finalposition-initial position) is zero,its average velocty is zero.
Oh I forgot about displacement.
Thank you very much.
To find the bird's average velocity, you need to divide the total distance traveled by the total time taken. In this case, you don't need to double the distance traveled.
The total distance traveled by the bird is given as 5190 km, and the total time taken is given as 13.8 days.
First, let's convert the distance from kilometers to meters. Since 1 km is equal to 1000 m, the total distance traveled by the bird is 5190 km * 1000 m/km = 5,190,000 m.
Next, let's convert the time from days to seconds. Since 1 day is equal to 24 hours, and 1 hour is equal to 60 minutes, and 1 minute is equal to 60 seconds, the total time taken by the bird is 13.8 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute = 1,191,360 seconds.
Now that we have the total distance traveled (5,190,000 m) and the total time taken (1,191,360 seconds), we can calculate the average velocity.
Average Velocity = Total Distance Traveled / Total Time Taken
Average Velocity = 5,190,000 m / 1,191,360 seconds
Calculating this value gives us the average velocity of the bird for the whole episode from leaving the nest to returning.