A spherical piece of metal has a radius of .250m and a mass of 503 kg. what is its specific gravity?
spgr=mass/volume=503000/(4/3 PI 25^3) I get a little less than 8
7.685
To find the specific gravity of the spherical piece of metal, we need to know the density of the metal and the density of water.
The specific gravity is defined as the ratio of the density of the substance to the density of water. In other words, it tells us how many times denser the substance is compared to water.
Density can be calculated using the formula:
Density = Mass / Volume,
where the mass is given as 503 kg.
The volume of a sphere can be calculated using the formula:
Volume = (4/3) * π * r^3,
where r is the radius of the sphere, given as 0.250 m.
So, the volume of the sphere is:
Volume = (4/3) * π * (0.250)^3.
Once we have the density of the metal, we can calculate the specific gravity by dividing the density of the metal by the density of water.
The density of water at 4 degrees Celsius is approximately 1000 kg/m^3.
Let's calculate the specific gravity step by step:
Step 1: Calculate the volume of the sphere:
Volume = (4/3) * π * (0.250)^3
Step 2: Calculate the density of the metal:
Density = Mass / Volume
Step 3: Calculate the specific gravity:
Specific Gravity = Density of Metal / Density of Water
Now, let's calculate these values:
Step 1:
Volume = (4/3) * π * (0.250)^3
Volume ≈ 0.065449 m^3
Step 2:
Density = 503 kg / 0.065449 m^3
Density ≈ 7688.78 kg/m^3
Step 3:
Specific Gravity = 7688.78 kg/m^3 / 1000 kg/m^3
Specific Gravity ≈ 7.69
Therefore, the specific gravity of the spherical piece of metal is approximately 7.69.