Calculate the concentration of all the ions and species in a solution (there are 6) made by dissolving 1.49 g of sodium resorcinate (Na2 C6H4O2) in 100.0 ml of distilled water.
To calculate the concentration of ions and species in a solution, you need to determine the number of moles of each component and then divide by the volume of the solution. Here's how you can do that for this specific case:
First, let's calculate the number of moles of sodium resorcinate (Na2C6H4O2) by dividing the given mass by its molar mass.
Molar mass of Na2C6H4O2:
= 2*22.99 + 6*12.01 + 4*16.00
= 45.98 + 72.06 + 64.00
= 182.04 g/mol
Number of moles of Na2C6H4O2:
= 1.49 g / 182.04 g/mol
= 0.00818 mol
Next, convert the volume of the solution from milliliters (ml) to liters (L).
Volume of the solution:
= 100.0 ml / 1000
= 0.1 L
Now, let's calculate the concentration of each ion and species.
For sodium ions (Na+):
Since each formula unit of sodium resorcinate contains two sodium ions (Na+), the number of moles of Na+ ions is twice the number of moles of Na2C6H4O2.
Number of moles of Na+:
= 2 * 0.00818 mol
= 0.01636 mol
Concentration of Na+:
= Number of moles of Na+ / Volume of the solution
= 0.01636 mol / 0.1 L
= 0.1636 M
Similarly, for C6H4O2 ions:
The number of moles of C6H4O2 ions is the same as the number of moles of Na2C6H4O2.
Number of moles of C6H4O2:
= 0.00818 mol
Concentration of C6H4O2:
= Number of moles of C6H4O2 / Volume of the solution
= 0.00818 mol / 0.1 L
= 0.0818 M
Please note that concentrations are typically measured in units of molarity (M), which represents the number of moles of a solute per liter of solution.