what pressure (atm) is exerted by a column of ethanol 86.0 cm high? the density of ethanol is 0.789 g/cm3 and 9.8 m/s2 as your gravitational constant.
To determine the pressure exerted by a column of ethanol, we can use the equation:
Pressure = Density × Gravitational Constant × Height
Given:
Density of ethanol = 0.789 g/cm3
Height of the column = 86.0 cm
Gravitational constant = 9.8 m/s2
First, we need to convert the density to SI units (kg/m3) and the height to meters.
Density of ethanol = 0.789 g/cm3 = 789 kg/m3 (1 g/cm3 = 1000 kg/m3)
Height of the column = 86.0 cm = 0.86 m (1 m = 100 cm)
Substituting the values into the equation:
Pressure = 789 kg/m3 × 9.8 m/s2 × 0.86 m
Calculating the result:
Pressure = 6773.692 Pa
Since 1 atmosphere (atm) is equal to 101325 Pa, we can convert the pressure to atm by dividing by 101325:
Pressure (in atm) = 6773.692 Pa / 101325 Pa
Calculating the final result:
Pressure (in atm) ≈ 0.067 atm (rounded to three decimal places)
Therefore, the pressure exerted by a column of ethanol 86.0 cm high is approximately 0.067 atm.