calculus

I need to find the dy/dx of x^2ln(x^2)I tried to do it the way I thought, but it did not come out right.

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  1. dy/dx= 2xlnx^2 + x^2/x^2 *2x
    reduce it.

  2. If I did it correctly I got 4x ln (x^2).

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  3. I got 2x (1+lnx^2)

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  4. You are right

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