# dy/dx

Ln (2x^2-3x)^4 how to solve it. I did the steps but none of my answers are the choices

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1. Solve it?

You mean what is the deriviative?

y=ln( u)
dy/dx=1/u * du/dx

so if u=(2x^2-3x)^4, then

du = 4( )^3 * (4x-3)

dy/dx=1/( )^4 * 4( )^3 * (4x-3)
=1/( ) * 4(4x-3)

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2. But when I do it none of the answers are right

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3. Really? According to whom?

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4. Did You mean: [ln(2x^2-3x)]^4

OR

ln[(2x^2-3x)^4]

Go to:

wolframalpha dot com

When page be open in rectangle type your function and click option =

Then click option Derivative:Show steps.

When you see steps you click on down left angle in Derivative field and you can save solution as image.

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