3) You make a solution by dissolving 3.4g Ba(OH)2 in enough water to make 450ml of salt solution.

a. What is the molarity of the solution?

calculate the number of moles you have from that mass.

Molarity=molesSolute/literssolution

To find the molarity of the solution, you need to calculate the number of moles of Ba(OH)2 and then divide it by the volume of the solution in liters.

The molar mass of Ba(OH)2 can be found by adding up the atomic masses of its elements:
Ba (barium) = 137.33 g/mol
O (oxygen) = 16.00 g/mol (there are two oxygen atoms)
H (hydrogen) = 1.008 g/mol (there are two hydrogen atoms)

So the molar mass of Ba(OH)2 is:
137.33 g/mol + 16.00 g/mol + 16.00 g/mol + 1.008 g/mol + 1.008 g/mol = 171.34 g/mol

Next, calculate the number of moles of Ba(OH)2 by dividing the mass given (3.4 g) by its molar mass:
moles = mass / molar mass = 3.4 g / 171.34 g/mol = 0.01987 mol

Now, convert the volume of the solution from milliliters to liters:
450 ml = 450/1000 L = 0.45 L

Finally, calculate the molarity (M) by dividing the number of moles (0.01987 mol) by the volume in liters (0.45 L):
Molarity = moles / volume = 0.01987 mol / 0.45 L = 0.044 g/L or 0.044 M

Therefore, the molarity of the solution is approximately 0.044 M.