Quadrilateral RSTU is a rectangle with diagonal RT. If m = 8x + 4 and = 3x – 2, find x.

the answer is x= 8

To find the value of x, we can set the expressions for the measures of the diagonals equal to each other.

Given:
Measure of diagonal RT = m = 8x + 4
Measure of diagonal SU = n = 3x - 2

Since these diagonals are equal in a rectangle, we can set them equal to each other:

8x + 4 = 3x - 2

To solve for x, we can now manipulate this equation:

8x - 3x = -2 - 4

Combine like terms:

5x = -6

Divide both sides of the equation by 5:

x = -6/5

Therefore, x is equal to -6/5.

To find the value of x, we will use the fact that the diagonals of a rectangle are equal in length. Given that the diagonal RT has a measure of 8x + 4 and the diagonal SU has a measure of 3x - 2, we can set up an equation:

8x + 4 = 3x - 2

To solve for x, we need to isolate the variable on one side of the equation. Let's start by getting rid of the constant terms on both sides:

8x - 3x = -2 - 4

Simplifying further:

5x = -6

Now, we can solve for x by dividing both sides of the equation by 5:

x = -6 / 5

Therefore, the value of x is -6/5.

and what is m?