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How many liters of water should be added to 20 liters of 40% solution of acid to obtain 30% solution?

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  1. Acid = 0.4 * 20 = 8 liters.
    Water = 0.6 * 20 = 12 lites.

    A / (A + W) = 0.30,
    8 / (8 + W) = 0.30,
    2.4 + 0.3W = 8,
    0.3W = 8 - 2.4 = 5.6,
    W = 18.7 Liters.

    18.7 - 12 = 6.7 Liters of water added.

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  2. x = liters of water

    .40(20) = .30(x + 20)

    8 = .30x + 6

    8 - 6 = .30x + 6 - 6

    2 = .30x

    2 / .30 = .30x / .30

    6.666 = x (which is also 6 2/3 as a fraction)

    6.7 ~ x

    6.7 liters of water is needed.

    or

    Six and two-third liters of water is need to obtain a 30% acid solution.

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