Given the following sets, select the statement below that is NOT true.
A = {b, l, a, z, e, r}, B = {b, a, l, e}, C = {a, b, l, e}, D = {l, a, b}, E = {a, b, l}
(Points : 2)
E ⊂ C
C ⊆ B
D ⊆ C
B ⊆ C
C ⊆ D
⊂ means a proper subset.
E⊂C means E is a proper subset of C, or "all elements of E are in C, AND E≠C".
C = {a, b, l, e}, E = {a, b, l}
Since a,b,l are in C, and E≠C, the statement is true.
There is one statement where the number members of the subset exceeds that of the set, which is impossible.
Can you find the statement?
To determine which statement is NOT true, we need to carefully compare each set.
A = {b, l, a, z, e, r}
B = {b, a, l, e}
C = {a, b, l, e}
D = {l, a, b}
E = {a, b, l}
Let's evaluate each statement and see if it holds:
1) E ⊂ C
This statement is true because all the elements of set E (a, b, l) are also present in set C (a, b, l, e).
2) C ⊆ B
This statement is not true. Set C is not a subset of set B because set C contains an additional element, 'e', which is not present in set B.
3) D ⊆ C
This statement is true because all the elements of set D (l, a, b) are also present in set C (a, b, l, e).
4) B ⊆ C
This statement is true because all the elements of set B (b, a, l, e) are also present in set C (a, b, l, e).
5) C ⊆ D
This statement is not true. Set C is not a subset of set D because set C contains an additional element, 'e', which is not present in set D.
Therefore, the statement that is NOT true is: C ⊆ B