What current flows when a 40 v potential difference is imposed across a 1.8 kÙ resistor?
Use Ohm's law in the form
I (in Amperes) = V/R
= 40 V/1.8*10^3 ohms
To calculate the current flowing through a resistor with a given potential difference, you can use Ohm's Law. Ohm's Law states that the current (I) flowing through a resistor is equal to the potential difference (V) across the resistor divided by the resistance (R) of the resistor.
The given potential difference is 40 V, and the resistance is 1.8 kΩ (which is equivalent to 1800 Ω).
Using Ohm's Law, we can calculate the current as follows:
I = V / R
I = 40 V / 1800 Ω
I = 0.022 A or 22 mA
Therefore, the current flowing through the 1.8 kΩ resistor is 0.022 Amperes (or 22 milliamperes).
To determine the current flowing through a resistor when a potential difference is applied, you can use Ohm's Law. Ohm's Law states that the current (I) flowing through a resistor is equal to the potential difference (V) applied across it, divided by the resistance (R) of the resistor.
Ohm's Law formula: I = V / R
In this case, the potential difference (V) is 40 volts and the resistance (R) is 1.8 kΩ (kilohms), which is equivalent to 1800 Ω (ohms).
Substituting the values into the formula: I = 40 V / 1800 Ω
Now you can calculate the current:
I ≈ 0.022 A
Therefore, the current flowing through the 1.8 kΩ resistor when a 40 V potential difference is imposed across it is approximately 0.022 Amperes.