A basketball player has a 40% shooting average from the free-throw line. If she takes two free throws, estimate the probability that she will make both of them. Use the following list of digits which was taken from a table of random numbers. Let the digits 0-3 represent a made free throw and let the digits 4-9 represent a miss. Start at the top left of the table and move all the way across to the right of the table before moving down to the next row.

Question

A basketball player has a 40% shooting average from the free-throw line. If she takes two free throws, estimate the probability that she will make both of them. Use the following list of digits which was taken from a table of random numbers. Let the digits 0-3 represent a made free throw and let the digits 4-9 represent a miss. Start at the top left of the table and move all the way across to the right of the table before moving down to the next row.

52052 24004 03845 11507
27510 33761 86563 61729
48061 59412 79969 11339
27324 72723 22406 86253
29970 95877 70975 99120

9)

_______
A)

B)

C)

D)

Answer 1

The probability of making two in a row is (2/5)^2 = 4/25.

I have no idea what the (A) - (D) part of your question is all about.

You could use the numerical entries to compute the actual fraction of free throws made, and the fraction of consecutive pairs of free throws made.

45 of 100 free throws were made (45%), which is better then the supposed average.

Try looking at "Related Questions" below

Answer 2

To estimate the probability that the basketball player will make both free throws, we need to count how many favorable outcomes there are (both made free throws) and divide it by the total number of possible outcomes.

Looking at the given table of random numbers, we can extract the relevant digits for the free throw outcomes. Since 0-3 represent made free throws and 4-9 represent misses, we can collect the digits in the table that fall in the range of 0-3.

The relevant digits for made free throws in the table are:

52052 24004 03845 11507
27510 33761 86563 61729
48061 59412 79969 11339
27324 72723 22406 86253
29970 95877 70975 99120

Now we need to count the number of times "0-3" (representing made free throws) appear in this list. By a quick count, we find that there are 12 instances where the digits are in the range of 0-3.

Next, we need to count the total number of possible outcomes. Since there are 20 digits in each row and 5 rows in total, the total number of digits in the table is 20 * 5 = 100. Therefore, the total number of possible outcomes is 100.

Now we can calculate the estimated probability by dividing the number of favorable outcomes (12) by the total number of possible outcomes (100):

Probability = 12/100 = 0.12

So, the estimated probability that the basketball player will make both free throws is 0.12 or 12%.

To answer the question, the correct answer would be:

A) 0.12 or 12%.