# math

15t^2+7t=2
The quadratic formula tells you that the solutions are:
t = [-b +/-sqrt (b^2 - 4ac]/ (2a)

In this case, a = 15, b = 7 and c = -2
solve the equation for t. What values for t will you get when you substitute the values you listed for a, b, and c in the quadratic formula?

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1. use your calculator to find the value of

t = (-7 + √169)/30 and (-7 - √169)/30

( I got t = 1/5 and -2/3 )

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2. POST IT.

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3. y^2-7y-8=0

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