15t^2+7t=2

The quadratic formula tells you that the solutions are:
t = [-b +/-sqrt (b^2 - 4ac]/ (2a)

In this case, a = 15, b = 7 and c = -2
solve the equation for t. What values for t will you get when you substitute the values you listed for a, b, and c in the quadratic formula?

use your calculator to find the value of

t = (-7 + √169)/30 and (-7 - √169)/30

( I got t = 1/5 and -2/3 )

POST IT.

y^2-7y-8=0

To solve the equation 15t^2 + 7t = 2 using the quadratic formula, we can substitute the values of a, b, and c into the formula.

The quadratic formula is given by:
t = [-b +/- sqrt(b^2 - 4ac)] / (2a)

In this case, a = 15, b = 7, and c = -2. Plugging these values into the formula, we have:

t = [-(7) +/- sqrt((7)^2 - 4(15)(-2))] / (2(15))

Simplifying further:

t = [-7 +/- sqrt(49 + 120)] / 30
t = [-7 +/- sqrt(169)] / 30
t = (-7 +/- 13) / 30

Now, we can find the two possible solutions for t by simplifying further:

1. t = (-7 + 13) / 30
t = 6/30
t = 1/5

2. t = (-7 - 13) / 30
t = -20/30
t = -2/3

Therefore, the values for t obtained when substituting the given values into the quadratic formula are t = 1/5 and t = -2/3.