Determine the volume of 0.150 M NaOH that neutralizes 0.188 g of a diprotic acid having a molar mass of 152.2 g/mol?

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  1. Let's let the diportic acid be H2A.
    The equation is
    H2A + 2NaOH ==> Na2A + 2H2O
    moles H2A = 0.188/152.2
    Convert moles H2A to moles NaOH using the coefficients in the balanced equation.
    Now convert moles NaOH to L using M = moles/L.

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