Solve, show the algebraic you use. Tammy has the following scores on her business law tests 92, 99, 84, 91. What score must she earn on her fifth test in order to have an A average? An A for her university starts at 90.
92 + 99 + 84 + 91 = 366
500 * 0.9 = 450
450 - 366 = ?
Ms. Sue, wher did you come up with 500*0.9?
The total possible points for 5 tests is 500. 90% of 500 = 450. Tammy needs a total score of 450 to get a 90% average.
Thank you, 450-366=84
You're welcome.
To solve this problem, we need to find the average of her test scores and determine the score she needs on her fifth test to maintain an A average.
Let's first calculate the average of her test scores:
Average = (Sum of scores) / (Number of scores)
Sum of scores = 92 + 99 + 84 + 91 = 366
Number of scores = 4
Average = 366 / 4 = 91.5
To maintain an A average, Tammy's average score needs to be at least 90. Therefore, she needs to score at least 90 on her fifth test.
Algebraically, we can represent the situation as follows:
(92 + 99 + 84 + 91 + x) / 5 ≥ 90
Where x represents the score she needs to earn on her fifth test.
Now, let's solve the inequality to find the value of x:
(366 + x) / 5 ≥ 90
Multiply both sides of the inequality by 5 to eliminate the fraction:
366 + x ≥ 450
Subtract 366 from both sides of the inequality:
x ≥ 450 - 366
x ≥ 84
Therefore, Tammy must score at least 84 on her fifth test to maintain an A average.