# Inequality

When I solve the inquality 2x^2 - 6 < 0,
I get x < + or - sqrt(3)

So how do I write the solution?
Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))?
Why?

Thanks.

So would this work?

abs x < ( sqrt 3 )

or
- sqrt 3<x<sqrt 3

I don't know the reason

fuji

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