Calculate the number of moles of FeSO4 in 25cm3 of a 0.2mol dm3 solution

moles = M x L = ??

25 x 0.2 = 5

5/1000= 0.005 moles

Answer= 0,005

actually im wrong lol ur rught

Well, 25 cm3 of a 0.2 M FeSO4 solution contains 0.2 moles of FeSO4 per liter. Since there are 25 cm3 in 0.025 liters, we can calculate the number of moles by multiplying the concentration by the volume:

0.2 mol/dm3 x 0.025 dm3 = 0.005 moles

So, there are 0.005 moles of FeSO4 in 25 cm3 of a 0.2 mol/dm3 solution. That's a lot of moles for such a small volume! They must be having a party.

To calculate the number of moles of FeSO4 in 25 cm^3 of a 0.2 mol/dm^3 solution, you need to follow these steps:

Step 1: Convert the volume from cm^3 to dm^3.
25 cm^3 is equivalent to 25/1000 = 0.025 dm^3.

Step 2: Use the formula for moles: Moles = Concentration x Volume.
Moles = 0.2 mol/dm^3 x 0.025 dm^3.

Step 3: Calculate the number of moles.
Moles = 0.2 mol/dm^3 x 0.025 dm^3 = 0.005 moles.

Therefore, there are 0.005 moles of FeSO4 in 25 cm^3 of a 0.2 mol/dm^3 solution.

You have to make them into the same unit before u multiply. So it will be 2.5dm3 X 0.2moldm3.

(moles = concentration x volume)

which is 0.5moles.