How many calories are absorbed by a copper spoon with a mass of 200 grams as it changes from 28°C to 33°C?
A) 0.00027
B) 3
C) 90
D) 13,000
And this one. How do i solve this one?
Look up the specific heat of copper. Call it C. Look for or compute its value with units of cal/(g*C) . You may find published values of C with different units, with kg or Joules.
The heat absorbed is
Q = M C*(delta T)
where delta T is the change in temperature, which is 5.0 C in this case. M is the mass in grams.
http://answers.yahoo.com/question/index?qid=20080310202708AAmEiZi
To solve this question, we can use the specific heat equation:
Q = mcΔT
where:
Q is the heat absorbed or released by the substance
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
In this case, we are looking for the amount of heat absorbed by a copper spoon. The specific heat capacity of copper is approximately 0.39 J/g·°C.
First, we need to calculate ΔT (change in temperature) by subtracting the initial temperature from the final temperature:
ΔT = final temperature - initial temperature
= 33°C - 28°C
= 5°C
Now, we can substitute the given values into the equation:
Q = (200 g)(0.39 J/g·°C)(5°C)
Q = 390 J
Converting the heat from joules to calories, we divide by the conversion factor:
Q = 390 J × (1 cal / 4.184 J)
Q ≈ 93.19 cal
Therefore, the amount of calories absorbed by the copper spoon as it changes from 28°C to 33°C is approximately 93.19 calories.
Looking at the answer choices provided, the closest value is C) 90 calories.