Given: BD is a diameter m 1 = 100°m BC = 30°
m 2 = ?degrees
Given: BD is a diameter m 1 = 100°m BC = 30°
m 3 = ? degrees
Given: BD is a diameter m 1 = 100°m BC = 30°
m 4 =? degrees
Given: BD is a diameterm 1 = 100°m BC = 30°
m AD = ?degrees
Given: BD is a diameter m 1 = 100°m BC = 30°
m CAB = ? degrees
Given: BD is a diameter m 1 = 100°m BC = 30°
m DAB = ? degrees
Given: BD is a diameter m 1 = 100°m BC = 30°
m ADB = ? degrees
To find the missing angles in relation to the given information, we need to use some properties of circles and angles.
1. m2: Since BD is a diameter, it creates a right angle at point B. So, angle m2 is 90 degrees.
2. m3: We can find m3 by using the property that the measure of an angle inscribed in a circle is half the measure of the intercepted arc. In this case, angle m3 is half the measure of arc BC. Since mBC is given as 30 degrees, m3 is also 30 degrees.
3. m4: The measure of angle m4 can be found by using the property that the measure of an angle inscribed in a semicircle is 90 degrees. Since BD is a diameter, it creates a semicircle. So, m4 is 90 degrees.
4. mAD: Angle mAD can be found by subtracting m3 from m1. Given m1 as 100 degrees and m3 as 30 degrees, we have mAD = m1 - m3 = 100 - 30 = 70 degrees.
5. mCAB: Again, we can use the property that the measure of an angle inscribed in a circle is half the measure of the intercepted arc. In this case, angle mCAB is half the measure of arc BD. Since BD is a diameter, the measure of the intercepted arc is 180 degrees. So, mCAB is half of 180 degrees, which is 90 degrees.
6. mDAB: Angle mDAB can be found by subtracting mCAB from m1. Given m1 as 100 degrees and mCAB as 90 degrees, we have mDAB = m1 - mCAB = 100 - 90 = 10 degrees.
7. mADB: Since BD is a diameter, it creates a right angle at point D. So, angle mADB is 90 degrees.
To summarize:
- m2 = 90 degrees
- m3 = 30 degrees
- m4 = 90 degrees
- mAD = 70 degrees
- mCAB = 90 degrees
- mDAB = 10 degrees
- mADB = 90 degrees
To find the values of angles 2, 3, 4, AD, CAB, DAB, and ADB, let's use the properties of angles in a circle.
1. Angle 2:
Since BD is a diameter, angle 2 is a right angle formed by the diameter and a chord. Therefore, angle 2 is 90 degrees.
2. Angle 3:
Angle 3 is an angle formed by the chord BC and the tangent BD. In a circle, the angle formed by the tangent and a chord is equal to half the measure of the intercepted arc. Therefore, angle 3 is equal to half the measure of arc BC, which is 15 degrees.
3. Angle 4:
Angle 4 is an angle formed by the chord BC and the tangent BD. Similar to angle 3, angle 4 is equal to half the measure of arc BC, which is 15 degrees.
4. Angle AD:
Since BD is a diameter, angle ADB is a right angle. The angle ADB is equal to 90 degrees, and since AD and DB are opposite rays, angle AD is also equal to 90 degrees.
5. Angle CAB:
Angle CAB is an angle formed by the tangent BD and the chord BC. In a circle, the angle formed by the tangent and a chord is equal to half the measure of the intercepted arc. Therefore, angle CAB is equal to half the measure of arc BC, which is 15 degrees.
6. Angle DAB:
Angle DAB is an angle formed by the chord BD and the tangent BC. Similar to angle CAB, angle DAB is equal to half the measure of arc BC, which is 15 degrees.
7. Angle ADB:
Since BD is a diameter, angle ADB is a right angle. The angle ADB is equal to 90 degrees, and since AD and DB are opposite rays, angle ADB is also equal to 90 degrees.
I have no idea what BD and BC signify. I assume that m signifies meters and º indicates degrees, but it is unclear how they go together.
If you want to designate exponents online, use "^", x^2 = x squared.