how many gram molecules are present in 4.9g of H2SO4
To find the number of gram molecules in a sample, we need to know the molar mass of the compound. The molar mass of H2SO4 (sulfuric acid) can be calculated as follows:
H2: 2 atoms x 1.0079 g/mol = 2.0158 g/mol
S: 1 atom x 32.06 g/mol = 32.06 g/mol
O4: 4 atoms x 16.00 g/mol = 64.00 g/mol
Total molar mass of H2SO4 = 2.0158 g/mol + 32.06 g/mol + 64.00 g/mol = 98.0858 g/mol
Next, we can use the formula:
Number of gram molecules = mass / molar mass
Number of gram molecules = 4.9 g / 98.0858 g/mol ≈ 0.05 mol
Therefore, there are approximately 0.05 gram molecules (or moles) of H2SO4 present in 4.9 grams of H2SO4.
To determine the number of gram molecules (also known as moles) present in 4.9g of H2SO4, we will use the concept of molar mass.
Step 1: Find the molar mass of H2SO4:
- The molar mass of hydrogen (H) is approximately 1g/mol.
- The molar mass of sulfur (S) is approximately 32g/mol.
- The molar mass of oxygen (O) is approximately 16g/mol.
Hence, the molar mass of H2SO4 can be calculated as follows:
(2 * 1g/mol for hydrogen) + (1 * 32g/mol for sulfur) + (4 * 16g/mol for oxygen) = 98g/mol.
Step 2: Calculate the moles of H2SO4:
Divide the given mass of H2SO4 (4.9g) by the molar mass (98g/mol):
4.9g / 98g/mol = 0.05 mol.
Therefore, there are 0.05 mole (or 0.05 gram molecules) of H2SO4 present in 4.9g of H2SO4.
Do you mean how many grams molecular weights are present in 4.9 g H2SO4? If so, that is just the number of moles.
moles = g/molar mass = 4.9/98 = ??
atomic mass of h+so=9.8
concteration: 4.9*5*98
%1000*1=2.401