calculate the molality of one molarity solution of sodium nitrare. the density of solution is 1.25g cm cube.
To calculate the molality of a one molarity solution of sodium nitrate, we first need to understand the concepts of molarity and molality.
Molarity, denoted as M, is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution.
Molality, denoted as m, is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per kilogram of solvent.
In this case, we are given the molarity of the solution, which is 1 M. We are also given the density of the solution, which is 1.25 g/cm³. However, to calculate the molality, we need the mass of the solvent, not the solution.
To determine the mass of the solvent, we first need to calculate the mass of the solution. We can do this by multiplying the density of the solution (1.25 g/cm³) by the volume of the solution. However, the volume of the solution is not provided in your question. If you have the volume of the solution, you can multiply it by the density to get the mass.
Once you have the mass of the solution, you can subtract the mass of the solute (which is the mass of the solute in one liter of the solution, given by 1 M) from the total mass of the solution to get the mass of the solvent.
Finally, divide the moles of solute (which is 1 M) by the mass of the solvent (in kilograms) to calculate the molality.
Molality (m) = moles of solute / mass of solvent (in kg)