A flower pot falls off a window ledge 10.0 m above the ground. Its velocity as it hits the ground is
A flower pot falls from a windowsill 8.0m above the pavement. Calculate the time taken for the flower pot to fall and the velocity at which it hits the pavement.
"Hey there! Did you hear about the flower pot? It really 'fell' for the ground! As for its velocity, well, without any other information, I can only say it's probably gonna be pretty fast. But hey, if it landed on a trampoline, maybe it bounced back up like a trapeze artist with springs in their shoes! Throw in a somersault and we've got ourselves a performance!"
To find the velocity of the flower pot as it hits the ground, we can use the equation of motion for free fall:
v^2 = u^2 + 2as
where:
- v is the final velocity (which we want to find)
- u is the initial velocity (which is 0 m/s in this case because the pot starts from rest)
- a is the acceleration due to gravity (approximately -9.8 m/s^2)
- s is the displacement or distance traveled (which is 10.0 m in this case)
Plugging in the values into the equation, we can solve for v:
v^2 = 0^2 + 2 * (-9.8 m/s^2) * 10.0 m
v^2 = -196 m^2/s^2
Taking the square root of both sides, we get:
v = √(-196 m^2/s^2)
Since the velocity cannot be negative in this context, we can ignore the negative sign:
v = √(196 m^2/s^2)
v ≈ 14 m/s
Therefore, the final velocity of the flower pot as it hits the ground is approximately 14 m/s.
To determine the velocity of the flower pot as it hits the ground, we need to consider the laws of motion and use the equation for free fall.
The equation for free fall is given by:
v = sqrt(2 * g * h)
Where:
v is the velocity of the object
g is the acceleration due to gravity
h is the height from which the object falls.
In this case, the height (h) is given as 10.0 m.
The acceleration due to gravity (g) is approximately 9.8 m/s^2.
Now, let's calculate the velocity:
v = sqrt(2 * 9.8 * 10.0) ≈ 14 m/s
Therefore, the velocity of the flower pot as it hits the ground is approximately 14 m/s.
v = g t
10 = (1/2) g t^2
t^2 = 20/9.8
t = 1.43 seconds to fall
so
v = 9.8 *1.43 = 14 meters/ second