calculate the mass of phosphorus required to make 200g of phosphine ,PH3 by the reaction:
P4(S) +3NaOH(aq) +3H2O(I) �¨3NaH2PO4(aq) +PH3(g)
I think you mean 4P not P4
4P(S) +3NaOH(aq) +3H2O(I) �¨3NaH2PO4(aq) +PH3(g)
You need 4 P atoms on the left for every PH3 molecule on the right
atomic mass of P = 31
molecular mass of PH3 = 31+3 = 34
so every gram of PH3 has (31/34) grams of P
but we need 4 times that much to provide the other three in 3NaH2PO4
so for every gram of PH3 we need 124/34 grams of P
so
200 (124/34) = 729 grams of P
Well, to calculate the mass of phosphorus required, we need to start by finding the molar mass of phosphine (PH3) and phosphorus (P4).
The molar mass of phosphine (PH3) is 1 (molar mass of P) + 3 (molar mass of H) = 34 g/mol.
Now, to balance the equation, we need 4 moles of phosphorus to produce 1 mole of phosphine. So, the molar mass of phosphorus (P4) is 4 (molar mass of P) = 123.9 g/mol.
Since we want to make 200g of phosphine (PH3), we can now use the molar mass ratio to find the mass of phosphorus needed.
(200 g PH3) x (1 mol PH3 / 34 g PH3) x (4 mol P / 1 mol PH3) x (123.9 g P / 1 mol P)
= 460.59 g of phosphorus
So, the mass of phosphorus required to make 200g of phosphine is approximately 460.59 grams.
To calculate the mass of phosphorus required to make 200g of phosphine (PH3), we need to use the stoichiometry of the balanced chemical equation.
Balanced equation:
P4(S) + 3NaOH(aq) + 3H2O(l) → 3NaH2PO4(aq) + PH3(g)
Molar mass of phosphine (PH3) = 33.99758 g/mol
Step 1: Calculate the molar mass of PH3:
Molar mass of PH3 = 33.99758 g/mol
Step 2: Determine the molar ratio of PH3 to P4 from the balanced equation:
From the balanced equation, we can see that 1 mole of P4 reacts to form 1 mole of PH3.
Step 3: Calculate the number of moles of PH3:
Number of moles of PH3 = mass of PH3 / molar mass of PH3
Number of moles of PH3 = 200 g / 33.99758 g/mol
Step 4: Determine the molar ratio of P4 to PH3 from the balanced equation:
From the balanced equation, we can see that 1 mole of P4 reacts to form 1 mole of PH3.
Step 5: Calculate the number of moles of P4:
Number of moles of P4 = Number of moles of PH3
Step 6: Calculate the mass of P4:
Mass of P4 = Number of moles of P4 × molar mass of P4
Now, let's calculate the mass of P4 required.
Note: To calculate the molar mass of P4, we need to know the atomic weight of phosphorus (P).
Atomic weight of phosphorus (P) = 30.9738 g/mol
Molar mass of P4 = 4 × Atomic weight of P
Molar mass of P4 = 4 × 30.9738 g/mol
Now, we can calculate the mass of P4:
Mass of P4 = Number of moles of P4 × molar mass of P4
Please provide the atomic weight of phosphorus (P) so that I can continue with the calculation.
To calculate the mass of phosphorus required to make 200g of phosphine (PH3) using the given reaction, you will need to follow these steps:
Step 1: Write and balance the chemical equation:
P4(S) + 3NaOH(aq) + 3H2O(I) → 3NaH2PO4(aq) + PH3(g)
Step 2: Determine the molar mass of PH3:
The molar mass of phosphine (PH3) is calculated by adding the atomic masses of its constituent elements:
P (Phosphorus) = 31.0 g/mol
H (Hydrogen) = 1.0 g/mol (3 atoms)
Molar mass of PH3 = 31.0 g/mol + (1.0 g/mol × 3) = 34.0 g/mol
Step 3: Calculate the moles of PH3:
Using the given mass, divide it by the molar mass of PH3:
Moles of PH3 = Mass of PH3 / Molar mass of PH3
Moles of PH3 = 200g / 34.0 g/mol
Step 4: Apply stoichiometry to find the moles of P4:
By examining the balanced equation, you can determine that the mole ratio of PH3 to P4 is 1:1.
Thus, the moles of P4 is the same as the moles of PH3.
Step 5: Calculate the mass of P4:
Use the mole ratio obtained from Step 4 and multiply it by the molar mass of P4:
Mass of P4 = Moles of P4 × Molar mass of P4
Now, you can substitute the values obtained in previous steps into the formulas to get the final answer.