In a shipment of 11 CD players, two are defective. Find the probability that a sample of 3 CD players will contain no more than one defective one.

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  1. Probably zero are defective:
    (9/11)(8/10)(7/9) = 0.5091

    Probability one is defective:
    (2/11)(9/10)(8/9)*3 = 0.4364

    No more than 1 defective (i.e. 0 or 1 defective):
    0.5091 + 0.4364 = 0.9455

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