Using the equations and enthalpy values provided, which mathematical expression can be used to determine the unknown enthalpy change of the decomposition of propane?
3 C + 3 O2 3 CO2 H =-1182 kJ
4 H2 + 2 O2 4 H2O H = -1144 kJ
C3H8 + 5 O2 3 CO2 + 4 H2O H = -2222 kJ
C3H8 3 C + 4 H2 H = ? kJ
(-1182) - [(-2222) + (-1144)]
(-2222) - [(-1182) + (-1144)]
(-1182) +(-1144) + (-2222)
(-2222) + (-1182) - (-1144)
I can't make out the question with no arrows to separate the products from the reactants. I'm not certain that supplying the arrows will help, either, because the board does not allow spacing after the first space.
To determine the unknown enthalpy change of the decomposition of propane (C3H8), we can use the given enthalpy values and equations to calculate it.
The balanced equation for the decomposition of propane is:
C3H8 -> 3C + 4H2
We are given the enthalpy change for the following reactions:
1. 3 C + 3 O2 -> 3 CO2 (H = -1182 kJ)
2. 4 H2 + 2 O2 -> 4 H2O (H = -1144 kJ)
3. C3H8 + 5 O2 -> 3 CO2 + 4 H2O (H = -2222 kJ)
To determine the enthalpy change for the decomposition of propane, we need to manipulate the given equations in such a way that the propane molecule is broken down into individual elements.
We can manipulate the given equations by summing up the enthalpy changes for the products and reactants. In this case, we need to ensure that the reactants of the balanced equations match the atoms present in the propane molecule.
Let's now calculate the unknown enthalpy change:
Unknown Enthalpy Change (H) = Enthalpy Change of Reactants - Enthalpy Change of Products
Reactants:
3 C -> C3 (C3 component of propane)
4 H2 -> 4H2 (H2 component of propane)
Products:
No products for the decomposition of propane since it breaks down into its constituent elements.
Now, let's calculate the unknown enthalpy change:
H = - (Enthalpy Change of Reactants - Enthalpy Change of Products)
= - (sum of enthalpies of C3 and 4H2 - sum of enthalpies of 3C and 4H2)
Now substitute the given enthalpy values into the equation:
H = - [(-1182) - [(-2222) + (-1144)]]
= - [(-1182) - (-3366)]
= - [1182 + 3366]
= - 4548 kJ
Therefore, the unknown enthalpy change for the decomposition of propane (C3H8 -> 3C + 4H2) is -4548 kJ.