Math

Solve: sin2xsinx - cos2xcosx = 1, x domain [-pi, pi].

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  1. or
    cos2xsinx - sin2xcosx = -1
    compare this to
    cos(A+B) = cosAcosB - sinAsinB
    looks like somebody expanded cos(2x+x)

    so cos 3x = -1 , (I know cos π = -1)
    3x = π
    x = π/3
    so for your given domain, x = ± π/3

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