y-2x=-5
3y-x=5
In the top equation:
1) y=2x -5
Put that in the second equation
3( ) -x =5
solve for x, then put that value of x back in to 1) to solve for y.
So would it be:
3(2x-5)=5?
would it?PLz help me bob and margie!
To solve the system of equations y-2x=-5 and 3y-x=5, you first need to rearrange one of the equations to solve for one variable in terms of the other. Let's rearrange the first equation, y-2x=-5, to solve for y:
y = 2x - 5
Now, substitute this expression for y into the second equation, 3y - x = 5:
3(2x - 5) - x = 5
Simplify the equation:
6x - 15 - x = 5
Combine like terms:
5x - 15 = 5
Next, isolate the variable x by moving the constant term to the other side:
5x = 5 + 15
5x = 20
Now, divide both sides of the equation by 5 to solve for x:
x = 20/5
x = 4
Once you have found the value of x as 4, substitute this value back into the expression for y:
y = 2x - 5
y = 2(4) - 5
y = 8 - 5
y = 3
Therefore, the solution to the system of equations is x = 4 and y = 3.