how many milliliters of hydrogen at 0 degree C and 1400 mmhg are produced if 15g of magnesium reacts with sulfuric acid?
See this worked example. After finding moles, use PV = nRT to solve for volume.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Tell solution
To determine the milliliters of hydrogen gas produced when 15g of magnesium reacts with sulfuric acid, we need to follow a few steps:
1. Write the balanced chemical equation for the reaction:
Mg + H₂SO₄ → MgSO₄ + H₂
According to the equation, one mole of magnesium reacts with one mole of sulfuric acid to produce one mole of hydrogen gas.
2. Calculate the moles of magnesium (Mg) used:
To do this, we need the molar mass of magnesium (24.31 g/mol).
Moles of Mg = mass of Mg / molar mass of Mg
Moles of Mg = 15g / 24.31 g/mol
3. Use the stoichiometry of the balanced equation to determine the moles of hydrogen (H₂) produced:
From the balanced equation, we know that one mole of magnesium reacts to produce one mole of hydrogen.
Moles of H₂ = Moles of Mg
4. Convert the moles of hydrogen gas to milliliters using the ideal gas law:
PV = nRT
P = pressure of the gas (1400 mmHg)
V = volume of the gas in milliliters (what we want to find)
n = moles of the gas (moles of H₂)
R = ideal gas constant (0.0821 L·atm/K·mol)
T = temperature in Kelvin (0°C + 273.15)
Rearranging the ideal gas law to solve for V:
V = (nRT) / P
Substituting the known values:
V = (moles of H₂ * 0.0821 L·atm/K·mol * temperature in Kelvin) / pressure in atm
However, we need to convert mmHg to atm, so we divide the pressure (1400 mmHg) by 760 mmHg/atm:
Pressure in atm = 1400 mmHg / 760 mmHg/atm
Now we can substitute the values into the equation to find the volume of hydrogen gas produced.
Note: The volume of hydrogen gas will be in liters, so we need to convert it to milliliters.
By following these steps, you should be able to calculate the milliliters of hydrogen gas produced when 15g of magnesium reacts with sulfuric acid at 0°C and 1400 mmHg.