Calculus derivative

Find the slope and an equation of the tangent line to the graph of the function f at the specified point.

f(x)=-1/3x^2+5x+5: (-1, -1/3)

Answer: f’(x)=-2/3x + 5

y=-2/3x -1

I re-worked the problem and got f'(x)=5, y=5x+ 14/3

This is from a multiple choice test and this is not an answer.

Can someone check my work?

  1. 👍 0
  2. 👎 0
  3. 👁 169
  1. Your derivative is correct
    Now use the value of x of the given point to find the slope
    slope = (-2/3)(-1) + 5
    = 2/3 + 5 = 17/3

    equation is
    y = (17/3)x + b
    sub in the point
    -1/3 = (17/3)(-1) + b
    16/3 = b

    equation: y = (17/3)x + 16/3

    1. 👍 0
    2. 👎 0
  2. Thanks. I was missing the step where you plug in the -1 to get slope.

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math(check)

    1)Find the range of the relation [(-1,4)},(2,5),(3,5)}.Then determine whether the relation is a funtion. 4,5,5 is the range 4,5 is a function 2)Find f(-1),if f(x)= x^2-6x/x+2 (-1)^2-6(-1)/-1+2 1+6/-1+2 7/1 =7 3)Find f(a),if f(t)=

    asked by erin on July 26, 2007
  2. calculus

    1. Which of the following expressions is the definition of the derivative of f(x) = cos(x) at the point (2, cos(2))? 2. Find the derivative of f(x) = |x + 2| at the point (1, 3) 3. Find f '(x) for f(x) = -2x3 + 3x2 - x + 15. 4.

    asked by mock on January 15, 2015
  3. I would like to understand my calc homework:/

    Consider the differential equation given by dy/dx=(xy)/(2) A) sketch a slope field (I already did this) B) let f be the function that satisfies the given fifferential equation for the tangent line to the curve y=f(x) through the

    asked by Amber on March 27, 2013
  4. Math

    Find the equation of the line tangent to curve x=sec(t), y=tan(t), at t=pi/6. I found th slope(derivative of the two which was csc(t). Plugged in Pi/6 and got 2 as the slope. Now how do I find the equation of the tangent? There

    asked by Beth on December 17, 2015
  1. Calculus - Functions?

    #1. A cubic polynomial function f is defined by f(x) = 4x^3 +ax^2 + bx + k where a, b and k are constants. The function f has a local minimum at x = -1, and the graph of f has a point of inflection at x= -2 a.) Find the values of

    asked by Amy on February 21, 2011
  2. Math (Secant Lines)

    Consider the function f(x)=sqrt(x) and the point P(4,2) on the graph of f? -Consider the graph f with secant lines passing through p(4,2) and Q(x,f(x)) for x-values 1, 3, and 5. -Find the slope of each secant line -Use the results

    asked by Ray on October 1, 2016
  3. Calculus

    1. a) For the Function and point below , Find f’(a). b) Determine the equation of the line tangent to the graph of f at (a,f(a)) for the given value of f(x) = 4x2+2x, a =1 F’(a) = y = 2. For the function find f’ using the

    asked by Tired on February 11, 2012
  4. calculus

    Let g be a function that is defined for all x, x ≠ 2, such that g(3) = 4 and the derivative of g is g′(x)=(x^2–16)/(x−2), with x ≠ 2. Find all values of x where the graph of g has a critical value. For each critical

    asked by Anonymous on December 1, 2016
  1. Calculus

    Find the slope m of the tangent line to the graph of the function at the given point and determine an equation of the tangent line. f(x) = 7 x - 2 x^2 text( at ) \(-1,-9\) m = y =

    asked by George A.J on January 31, 2011
  2. math

    Find the slope m of the tangent line to the graph of the function at the given point and determine an equation of the tangent line. f(x)=7x-5x^2 at (-2,-34) m = ?? y = ?? .

    asked by Kimberly on March 4, 2013
  3. Calculus

    The equation dy/dx = -6x^2/y gives the slope at any point on the graph of f(x). The range of f(x) is [0, infinity] and f(1) = 2. A. Find the equation of the tangent line to f(x) at the point (1,2). B. Write the function f(x). C.

    asked by Anonymous on April 23, 2016
  4. Math (Calculus) (mean value theorem emergency)

    Consider the graph of the function f(x)=x^2-x-12 a) Find the equation of the secant line joining the points (-2,-6) and (4,0). I got the equation of the secant line to be y=x-4 b) Use the Mean Value Theorem to determine a point c

    asked by Ray on November 19, 2016

You can view more similar questions or ask a new question.