trignometry

Prove That 2sin^pi/6 + cosec^7pi/6cos^pi/3 = 3/2

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  1. Your expression makes no sense
    We use the ^ symbol as an exponent sign.

    so your 2 sin^π/6 would be
    2(sin)^(π/6) which is meaningless

    if you simply meant:
    2 sin(π/6) + cosec(7π/6)cos(π/3)
    that would be
    2(1/2) + (-2)(1/2) = 0

    retype your problem.

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