A certain diet requires at least 60 units of carbohydrates, 45 units of protein, and 30 units of fat each day. Each ounce of Supplement A provides 5 units of carbohydrates, 3 units of protein, and 4 units of fat. Each ounce of Supplement B provides 2 units of carbohydrates, 2 units of protein, and 1 unit of fat. If Supplement A costs $1.50 per ounce and Supplement B costs $1.00 per ounce, how many ounces of each supplement should be taken daily to minimize the cost of the diet?

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To minimize the cost of the diet, we need to find the number of ounces of Supplement A (A) and Supplement B (B) that will meet the daily requirements at the lowest cost.

Let's assume we need x ounces of Supplement A and y ounces of Supplement B.

The cost equation can be written as: Cost = 1.50x + 1.00y.

Now, let's set up the equations based on the nutritional requirements:

For carbohydrates:
5x + 2y ≥ 60

For protein:
3x + 2y ≥ 45

For fat:
4x + y ≥ 30

To convert these equations into equations of equality, we equate them to their respective requirements:

For carbohydrates:
5x + 2y = 60

For protein:
3x + 2y = 45

For fat:
4x + y = 30

We then solve this system of equations using standard methods such as substitution or elimination.

Here, we will use the substitution method. First, solve the fat equation for y:

y = 30 - 4x

Now substitute this value of y into the other two equations:

5x + 2(30 - 4x) = 60
3x + 2(30 - 4x) = 45

Simplifying these equations:

5x + 60 - 8x = 60
3x + 60 - 8x = 45

-3x = 0
-5x = -15

Solving for x:

x = 0

Substitute this value back into y = 30 - 4x to find y:

y = 30 - 4(0)
y = 30

Therefore, x = 0 and y = 30. This means we need 0 ounces of Supplement A and 30 ounces of Supplement B to meet the daily requirements.

Now, plug these values into the cost equation to find the minimum cost:

Cost = 1.50(0) + 1.00(30)
Cost = $30

So, the minimum cost of the diet is $30 when 0 ounces of Supplement A and 30 ounces of Supplement B are taken daily.