# Algebra

write an equation of the line containing the given point and parallel to the given line (2,-4); 8x-3y=2 the equation of the line is y=

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1. figure slope first.

slope first: 3y=8x-2, or y= 8/2 x=2/3
slope is 2/3

Then, the line

y= mx+b
y= 8/3 x +b put in (2,-4), and solve for b, thence you have the line.

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2. since it is parallel to 8x - 3y = 2, the new line will differ only in the constant.

let the new line be 8x - 3y = c
plug in the given point (2,-4)
16 + 12 = c = 28

8x - 3y = 28

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