Algebra

Find an equation of the line having the given slope and containing the given point.
M=4/5, (7,-8)

I can totally due the equation
y+8=4/5x-28/5
but keep getting the answer wrong. I cannot figure out how subtracting 8 they get the answer
y=4/5x-68/5

PLEASE HELP!

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  1. I know how to "due" the equation also,and here it is.

    y=mx+b
    put in the y,x, knowing m
    -8=4/5 *7 + b solve for b.
    -8=28/5+b
    -40=28+5b
    5b=-68
    b=-68/5

    y=4/5 x -68/5
    I have no idea what your work is, it makes no sense to me.

  2. In your work, you forgot the brackets
    it should be
    y+8 = (4/5)(x-7)

    now multiply by 5 to get rid of fractions
    5y + 40 = 4x - 28
    4x - 5y = 68

    rearrange to get the same answer as bobpursley gave you

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  3. the formula I'm suppose to be using is y-y1=m(x-x1)
    m=4/5 (7,-8)

    I don't understand your answer

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  4. that is exactly the formula I used for you

    y - y1 = m(x - x1)
    y -8 = (4/5)(x-7)

    I then described what I did next
    4x - 5y = 68
    -5y = -4x + 68
    divided everybody by -5
    y = (4/5)x - 68/5

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