Find an equation of the line having the given slope and containing the given point.
M=4/5, (7,-8)
I can totally due the equation
y+8=4/5x-28/5
but keep getting the answer wrong. I cannot figure out how subtracting 8 they get the answer
y=4/5x-68/5
PLEASE HELP!
I know how to "due" the equation also,and here it is.
y=mx+b
put in the y,x, knowing m
-8=4/5 *7 + b solve for b.
-8=28/5+b
-40=28+5b
5b=-68
b=-68/5
y=4/5 x -68/5
I have no idea what your work is, it makes no sense to me.
In your work, you forgot the brackets
it should be
y+8 = (4/5)(x-7)
now multiply by 5 to get rid of fractions
5y + 40 = 4x - 28
4x - 5y = 68
rearrange to get the same answer as bobpursley gave you
the formula I'm suppose to be using is y-y1=m(x-x1)
m=4/5 (7,-8)
I don't understand your answer
that is exactly the formula I used for you
y - y1 = m(x - x1)
y -8 = (4/5)(x-7)
I then described what I did next
4x - 5y = 68
-5y = -4x + 68
divided everybody by -5
y = (4/5)x - 68/5
To find the equation of a line, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope of the line.
Given the slope, m = 4/5, and the point (7, -8), we can substitute these values into the point-slope form to find the equation of the line.
Plugging in the values, we have:
y - (-8) = (4/5) * (x - 7)
Simplifying further:
y + 8 = (4/5)x - (4/5) * 7
y + 8 = (4/5)x - 28/5
Now, let's rearrange the equation to solve for y:
y = (4/5)x - 28/5 - 8
y = (4/5)x - 28/5 - 40/5
y = (4/5)x - 68/5
This is the correct equation of the line. The mistake in your calculation might have occurred when distributing the slope of (4/5) to both terms inside the parentheses. You must multiply it by each term individually:
(4/5) * x = (4/5)x
(4/5) * 7 = (4/5) * 7/1 = 28/5
Then, when combining like terms and simplifying further, you should subtract 40/5 from -28/5 to get -68/5.