MATH

If two dice are rolled, what is the probability of rolling a sum of 6, given that doubles are not rolled?

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  1. Ways to get a sum of six
    =|{(1,5),(2,4),(4,2),(5,1)}|
    = 4 ways
    given that doubles are not rolled, therefore (3,3) was absent.
    Total number of ways:
    6 faces * (6-1) faces to eliminate doubles
    = 30

    So probability of rolling a total of 6
    = P(6)
    = ?

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