how many grams of Copper (II) sulfate pentahydrate would you use to make 400.0 mL of .750 M solution?
How many moles do you need in the final solution? That is moles = M x L = ??
How many grams is that?
moles = grams/molar mass. Solve for grams.
To determine the number of grams of Copper (II) sulfate pentahydrate needed to make a 400.0 mL solution with a concentration of 0.750 M, you need to follow these steps:
Step 1: Find the molar mass of Copper (II) sulfate pentahydrate.
Copper (II) sulfate pentahydrate, CuSO4 · 5H2O, consists of a copper ion (Cu2+), a sulfate ion (SO42-), and five water molecules. The molar mass can be calculated by adding the molar masses of the individual elements in the compound. The molar masses are as follows:
Copper (Cu) = 63.55 g/mol
Sulfur (S) = 32.07 g/mol
Oxygen (O) = 16.00 g/mol
Hydrogen (H) = 1.01 g/mol
The molar mass of Copper (II) sulfate pentahydrate is calculated as follows:
Molar mass = (1 × atomic mass of Cu) + (1 × atomic mass of S) + (4 × atomic mass of O) + (10 × atomic mass of H) + (5 × atomic mass of O)
Step 2: Calculate the number of moles of Copper (II) sulfate pentahydrate needed.
To find the number of moles, you can use the formula:
Moles = concentration (M) × volume (L)
Given that the volume is 400.0 mL, you need to convert it to liters:
Volume (L) = 400.0 mL ÷ 1000 = 0.4 L
Now, use the formula to calculate the number of moles:
Moles = 0.750 M × 0.4 L
Step 3: Convert moles to grams of Copper (II) sulfate pentahydrate.
To convert moles to grams, you need to multiply the number of moles by the molar mass of Copper (II) sulfate pentahydrate calculated in Step 1.
Once you perform these calculations, you will get the number of grams of Copper (II) sulfate pentahydrate needed to make a 400.0 mL solution with a concentration of 0.750 M.