A body moves 6 meters north than 8 meters east than 10 meters vertically upward. What is its resultant displacement from initial position?

sqrt[6^2 + 8^2 + 10^2) = sqrt(200)

= 14.14 m

To find the resultant displacement, you need to find the sum of the individual displacements in each direction.

Let's break down the problem:

1. The body moves 6 meters north. This gives us a displacement of +6 meters in the north direction.

2. Next, the body moves 8 meters east. This gives us a displacement of +8 meters in the east direction.

3. Finally, the body moves 10 meters vertically upward. This gives us a displacement of +10 meters in the upward direction.

Now, let's add up these displacements:

In the north direction: +6 meters
In the east direction: +8 meters
In the upward direction: +10 meters

To find the resultant displacement, we can use the Pythagorean theorem. The Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. In this case, we can consider the north and east displacements as the sides of a right triangle, and the resultant displacement as the hypotenuse.

Using the Pythagorean theorem, we have:

Resultant displacement (R) = √(North displacement^2 + East displacement^2 + Upward displacement^2)

R = √(6^2 + 8^2 + 10^2)
R = √(36 + 64 + 100)
R = √200
R = 14.14 meters (rounded to two decimal places)

Therefore, the resultant displacement from the initial position is approximately 14.14 meters.