physics

a point charge 50*10 raise to the power -6 C is located in the XY plane at the position vector r0= 2i^+3j^. what is the electric field at the point of position vector r=8i^+5j^?

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  1. E=kq (rvector)/(magnitude rvector)^3

    rvector= displacement=(6i+2j)

    and rvector= sqrt(6^2+2^2)=sqrt40
    so magnitude rvector ^3=40sqrt40
    check that

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