Determine the vertical component of a baseball's velocity if the ball is thrown at 28 m/sec at an angle of 37 degrees with the horizontal.
The answer is 21.2 m/sec but I have no clue on how to solve this problem.
draw the figure. The vertical component is 28sin37, the horizontal component is 28cos37
Thanks,
my book provides the answer as 21.2 m/sec, I calculated the vertical component 28sin37=16.85 but since it did not match the correct answer I thought I needed another step. There has to be because your answer isn't even a choice.
To determine the vertical component of a projectile's velocity, you need to use trigonometry. Here's how you can solve this problem step-by-step:
1. Identify the given information:
- Initial velocity (magnitude): 28 m/sec
- Angle with the horizontal: 37 degrees
2. Split the initial velocity into horizontal and vertical components:
- The horizontal component of velocity (Vx) remains constant throughout the motion and is given by:
Vx = V * cos(theta), where V is the magnitude of the initial velocity and theta is the angle with the horizontal.
- The vertical component of velocity (Vy) changes due to acceleration (provided there is no air resistance) and is given by:
Vy = V * sin(theta), where V is the magnitude of the initial velocity and theta is the angle with the horizontal.
3. Substitute the values into the formulas:
- Vx = 28 * cos(37)
- Vy = 28 * sin(37)
4. Calculate the vertical component of velocity:
- Vy = 28 * sin(37)
- Vy = 16.9 m/sec
Therefore, the vertical component of the baseball's velocity is 16.9 m/sec.
To find the answer of 21.2 m/sec, there might be an error in either the given data or the solution provided. Please double-check the values if necessary.