give the value of: Tan(Arctan x+1/x-1+Arctan x-1/x)
let arctan((x-1)/x) = B or tanB = (x-1)/x then Tan(Arctan x+1/x-1+Arctan x-1/x) = tan(A+B) = (tanA + tanB)/(1-tanAtanB) = [ (x+1)/(x-1) + (x-1)/x ] / [1 - (x+1)/(x-1)(x-1)/x ] = .... = (2x^2 - x + 1)/(1-x) check my algebra
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