A square coil of side 0.5 m is placed with its plane perpendicular to the direction of the magnetic field. What is the flux change in the coil if the magnetic field changes from 0.1 Tesla to 0.5 Tesla?
Choose one answer.
a. 0.1 Weber
b. 0.2 Weber
c. 0.8 Weber
d. 1.6 Weber
the area is 0.5*0.5 but im stuck
To calculate the flux change in the coil, you need to use the formula:
Flux (Φ) = Magnetic Field (B) x Area (A) x cos(θ)
Where:
- Flux (Φ) represents the measure of the total magnetic field passing through a given surface.
- Magnetic Field (B) represents the strength of the magnetic field.
- Area (A) represents the area of the coil.
- θ represents the angle between the magnetic field direction and the plane of the coil. In this case, the coil is placed with its plane perpendicular to the direction of the magnetic field, so θ = 90° and cos(θ) = 0.
Given that the side of the square coil is 0.5 m, the area of the coil would be (0.5 m) x (0.5 m) = 0.25 m².
Now, let's calculate the flux change:
Initial flux (Φinitial) = Binitial x A x cos(θ) = 0.1 Tesla x 0.25 m² x cos(90°) = 0.1 Weber
Final flux (Φfinal) = Bfinal x A x cos(θ) = 0.5 Tesla x 0.25 m² x cos(90°) = 0.5 Weber
To find the flux change, we subtract the initial flux from the final flux:
Flux change = Φfinal - Φinitial = 0.5 Weber - 0.1 Weber = 0.4 Weber
Therefore, the correct answer is c. 0.8 Weber.