the answer is 3.9 can anyone please explain how do you get this answer? Thank you
we can change bases by logloga b = log b/log a , (base 10) so your equation is logx/log3 + logx/log6 = 2 logx(1/log3 + 1/log6) = 2 logx = 2/(1/log3 + 1/log6) = .59154 appr. x = 10^.59154 = 3.904
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