Chemistry

The following volumes of 0.000300 M SCN are diluted to 15.00mL determine the concentration of SCN in each sample after dilution.

Sample 0.000300 M SCN(ml) SCN (M)
1 1.50
2 3.50

Can someone please explain how to do this?

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  1. Should have been in a table but i guess it could not fit there.

    Sample 1 = 1.50 (0.000300M SCN (mL)), SCN (M) = ?

    sample 2 = 3.50 (0.000300M SCN (mL)), SCN (M) = ?

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  2. You take 1.50 mL and dilute to 15.00; therefore, the new concn is
    0.00030 x (1.50/15.00) = ??
    If you prefer, you can use the dilution formula of c1v1 = c2v2 which is the same as mL1 x M1 = mL2 x M2

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