# Chemistry

The following volumes of 0.000300 M SCN are diluted to 15.00mL determine the concentration of SCN in each sample after dilution.

Sample 0.000300 M SCN(ml) SCN (M)
1 1.50
2 3.50

Can someone please explain how to do this?

1. 👍 0
2. 👎 0
3. 👁 497
1. Should have been in a table but i guess it could not fit there.

Sample 1 = 1.50 (0.000300M SCN (mL)), SCN (M) = ?

sample 2 = 3.50 (0.000300M SCN (mL)), SCN (M) = ?

1. 👍 0
2. 👎 0
2. You take 1.50 mL and dilute to 15.00; therefore, the new concn is
0.00030 x (1.50/15.00) = ??
If you prefer, you can use the dilution formula of c1v1 = c2v2 which is the same as mL1 x M1 = mL2 x M2

1. 👍 0
2. 👎 0

## Similar Questions

1. ### chemistry

Assume that it is necessary to determine the [FE^3+ in a solution that may be 0.0001 to 0.0005 M range . Outline the spectrophotometric method that would accurately give the required data. Be spectific about the solutions that you

asked by jxv on November 13, 2016
2. ### science-CHEM

Fe+3 + SCN- ==Fe(SCN)+2 if adding NaOH will form precipitates, but what is the precipitates' formula? And after this reaction, if we add HCl to the reaction, will the precipitates dessolve? What does the HCl affect the reaction?

asked by Nicola on November 21, 2008
3. ### chemistry

71.0 mL of a 1.30 M solution is diluted to a total volume of 238 mL. A 119-mL portion of that solution is diluted by adding 105 mL of water. What is the final concentration? Assume the volumes are additive.

asked by mat choma on September 28, 2016
4. ### Chemistry

A student mixes 5.0 mL of 0.00200 M Fe(NO3)3 with 5.0 mL 0.00200 KSCN. She finds that the concentration of FeSCN2+ in the equilibrium mixture is 0.000125 M. Follow these steps to determine the corresponding experimental value of

asked by anon on March 10, 2015
1. ### Chemistry

Quick question, since FePO4 is insoluble, will that mean a precipitate will form? During the experiment I don't remember seeing a precipitate. Is that my error, or is the precipitate hard to see? Sure. Adding Na3PO4 will make a

asked by Karl on December 17, 2006
2. ### Chem

There are three questions in particular that I am having problems with. Here they are 1. A standard solution of FeSCN2+ is prepared by combining 9.00 mL of 0.200 M Fe(NO3)3 w/1.00 mL of 0.0020 M KSCN. The equilibrium concentration

asked by Mark on January 19, 2009
3. ### Chemistry

A reaction mixture of 4.0 mL of 0.002 M SCN- and 5.0 mL of 0.002 M Fe3+ is diluted to 10.0 mL with 0.1 M HNO3 to form the blood-red FeNCS2+ complex. The equilibrium molar concentration of the FeNCS2+ determined from a

asked by Anonymous on March 18, 2013
4. ### chemistry

A reaction mixture of 4.0 mL of 0.002 M SCN- and 5.0 mL of 0.002 M Fe3+ is diluted to 10.0 mL with 0.1 M HNO3 to form the blood-red FeNCS2+ complex. The equilibrium molar concentration of the FeNCS2+ determined from a

asked by Anonymous on October 13, 2015
1. ### Chemistry

For preparing a set of standard solutions of FeNCS2+, the equilibrium molar concentration of FeNCS2+ is assumed to equal the initial molar concentration of the (SCN-) in the reaction mixture. why is this assumption valid?

asked by Chemistry on September 17, 2017
2. ### chemistry

The concentration and volume of reagents combined in each trial are listed in the table below: Trial 00020 M 00020 M H2O(mL) Fe(NO3)3 (mL) KSCN (mL) 1 5 2 3 2 5 3 2 3 5 4 1 4 5 5 0 Initially (right after combining and before any

asked by temperance on April 9, 2008
3. ### chemistry

balance the following chemical equation Fe2(So4)3 + KSCN = K3Fe(SCN)6 + K2So4 my answer: Fe2(So4)3 + 12 KSCN = 2 K3Fe(SCN)6 + 3 K2So4 is my answer correct?

asked by anonymous on September 16, 2019
4. ### chemistry

Suppose that the reaction of Fe3+ and SCN- produces Fe(SCN)2 (+). 5.00mL of 2.0mM Fe3+ is mixed with 5.00 mL of 2.0mM SCN-. The student finds the equilibrium concentrations of Fe(SCN)2(+) to be 0.3mM. 1.) What is the initial

asked by paula on February 23, 2015