Log base 10 of 9 = 0.95. Log base 10 of 2 = 0.30. Find log base 10 of (20/9)
log(20/9)=log20-log9=log10+log2-log9=
=1+0.30-0.95
To find the logarithm base 10 of a number, we can use the logarithmic identity:
log_b(a * b) = log_b(a) + log_b(b)
In this case, we want to find log base 10 of (20/9), which can be expressed as:
log_10(20/9)
Using the logarithmic identity, we can split this expression into two separate logarithms:
log_10(20) - log_10(9)
Now, we know the values of log base 10 of 20 and log base 10 of 9 from the given information.
log base 10 of 20 = 0.95
log base 10 of 9 = 0.30
So the calculation becomes:
0.95 - 0.30
We can subtract these two values to get the final answer:
0.95 - 0.30 = 0.65
Therefore, the log base 10 of (20/9) is 0.65.