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justin had nickels and dimes in his pocket. When he counted out his change, he had 80 cent. if there are 12 coins altogether, how many dimes did he have?

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  1. n+d = 12
    5n+10d = 80 or n + 2d = 16

    subtract them ---> d = 4
    sub into first --- n+4=12
    n = 8

    he has 8 nickels and 4 dimes.

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